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Old 10-20-2009, 01:47 PM   #38 (permalink)
Schmitti
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Join Date: Apr 2006
Location: Schen. NY

If you need me to put everything into a easily readable formula it can be done.

A lot of what we used were very simple ballistic calculators. Pure physics that takes into account the diameter of the ball, it's mass, the affect of gravity, the velocity that the projectile is fired at. Not crazy complex stuff... just a standard formula.

The formula that Carter used in his 2nd video to come up with the Foot-pounds (energy) (FPE) needed to break a paintball comes from the equation/calculation to determine the work performed as an object falls from some height. This equation uses mass, gravity, and height.

W=mgh

It's derived from the equations on this page...
Solve problem related to impact force from falling object

W= 1/2(mvf^2) - 1/2(mvi^2)

Where vf is final velocity (impact velocity), vi is initial velocity.

Vf is calculated from: vf = square root (2gh)

Basically because there is no initial velocity (the ball is being dropped), that portion of the W equation is zero .. so you are left with 1/2(mvf^2)... substitute square root (2gh) into the equation for vf

You now have W = 1/2(m2gh) = mgh

That's where that math came from.

Any questions?

E
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