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Old 03-18-2013, 07:57 PM   #1 (permalink)
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Anybody good at math?

Figured I'd ask my math question here since i've had luck at it before. I'm not trying for you guys to do my math homework, but rather help me figure out how to do it for my test tomorrow.

First type of problems:

Convert from polar equation to rectangular equation.

cis=cos+sin

3cis(pi/4)
cis0
5cis(3pi/4)
Etc
Etc

Second type of problem:

Put in Polar Form:

Z1Z2 Z1: 7cis(5pi/2) Z2: 8cis(3pi/4)


Like I stated, I don't need the answers, I would simply like to know how to get there. Any help is appreciated!!
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Old 03-18-2013, 08:25 PM   #2 (permalink)
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The answer is: MAYO
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Old 03-18-2013, 08:28 PM   #3 (permalink)
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Quote:
Originally Posted by gainman View Post
The answer is: MAYO
Correction, MAYO^Mar=sin(rape)
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Old 03-18-2013, 08:29 PM   #4 (permalink)
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Quote:
Originally Posted by Nbanwart View Post
Figured I'd ask my math question here since i've had luck at it before. I'm not trying for you guys to do my math homework, but rather help me figure out how to do it for my test tomorrow.

First type of problems:

Convert from polar equation to rectangular equation.

cis=cos+sin

3cis(pi/4)
cis0
5cis(3pi/4)
Etc
Etc

Second type of problem:

Put in Polar Form:

Z1Z2 Z1: 7cis(5pi/2) Z2: 8cis(3pi/4)


Like I stated, I don't need the answers, I would simply like to know how to get there. Any help is appreciated!!
is this some grade school **** that you'll never use again and forget forever? because i don't think i've seen these ever before even though i vaguely remember the term "polar equation...."

if no one else can help, refer to your textbook. sometimes they explain better than the teachers, depending on the teacher. what does your textbook say?
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Old 03-18-2013, 08:32 PM   #5 (permalink)
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Quote:
Originally Posted by heinous View Post
is this some grade school **** that you'll never use again and forget forever? because i don't think i've seen these ever before even though i vaguely remember the term "polar equation...."

if no one else can help, refer to your textbook. sometimes they explain better than the teachers, depending on the teacher. what does your textbook say?
That's exactly the problem, the problem is different than anything the textbook has to offer as the teacher does handwritten (she creates them) assignments.

Here's how to do the first set, I think, the second set I am still not sure of.

Polar - rectangular conversion
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Old 03-18-2013, 08:33 PM   #6 (permalink)
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I thought I was good at math...until I read this. Four year of calculus in college, and I have no idea what that is saying. (Now, I haven't used anything past fractions and basic algebra and geometry since college, so maybe I have just forgot it.)
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Last edited by MrBig; 03-18-2013 at 08:36 PM.
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Old 03-18-2013, 08:37 PM   #7 (permalink)
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Quote:
Originally Posted by MrBig View Post
I thought I was good at math...until I read this. Four year of calculus in college, and I have no idea what that is saying. (Now, I haven't used anything passed fractions and basic algebra and geometry since college, so maybe I have just forgot it.)
This is just pre-cal graphing unit circle I doubt it's too complicated, just looks that way and has to be totally useless knowledge.
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Old 03-18-2013, 08:44 PM   #8 (permalink)
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i know the unit circle and degrees labeled in radians but i don't remember this...

i think you're just converting polar equations to y=mx+b form, hope that helps.
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Old 03-18-2013, 09:04 PM   #9 (permalink)
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Old 03-18-2013, 09:09 PM   #10 (permalink)
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Quote:
Originally Posted by MrBig View Post
I thought I was good at math...until I read this. Four year of calculus in college, and I have no idea what that is saying. (Now, I haven't used anything past fractions and basic algebra and geometry since college, so maybe I have just forgot it.)
Dont feel so bad. It looks like some funky trig notation. Never really seen someone combine sin and cos before into cis before.
But polar to rectangular coordinate conversions can be useful and has its applications. Its just really weird, when someone decides to throw in cis in there.
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