mcarterbrown.com  

General Chat MCB's Coffee House: Pull up a seat, and grab your favorite caffeinated beverage. Non-paintball related chat within.

Reply
 
Thread Tools
Old 09-14-2008, 04:48 PM   #11 (permalink)
www.tituspb.com
 
Titus's Avatar
 
Join Date: Mar 2006
Location: The Group W Bench

I thought this thread was going to be about needing help with a PB trigger.

And I still hate math!
__________________
Feedback
Dealer for APP, CCI, Nelson, Leland, Valken, Tippmann, & Procaps.

Please donate to make a difference in my fathers life
Willing to be a 3rd party for shipments to Canada anywhere in the world just PM me.
Buy a Celanis Paintball Patch for a good cause
http://stationcaster.com/player_skin...=4751&f=855201 < Radio Ad
Titus is offline   Reply With Quote
Old 09-14-2008, 05:41 PM   #12 (permalink)
The Furry Tailed One
 
skiddish9999's Avatar
 
Join Date: Sep 2007
Location: Damn it's hot, Florida

Thank you all for the help...

I actually got through analytical geometry and I passed calculus this was all back in high school...thanks for the links as well I hope they work...My homework is due in 6 hours and 18 minutes...
__________________
MCB FeedBack

Quote:
Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
skiddish9999 is offline   Reply With Quote
Old 09-14-2008, 08:55 PM   #13 (permalink)
The Furry Tailed One
 
skiddish9999's Avatar
 
Join Date: Sep 2007
Location: Damn it's hot, Florida

Just a few left...Anybody?
__________________
MCB FeedBack

Quote:
Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
skiddish9999 is offline   Reply With Quote
Old 09-14-2008, 09:14 PM   #14 (permalink)
Bigger Balls
 
Siress's Avatar
 
Join Date: Sep 2006
Location: Atlanta, GA

(I'm procrastinating my homework by doing yours... )

LarPreCalcAGA5 5.2.046.] Use the given function value(s) and trigonometric identities to find the indicated trigonometric functions.
sec(θ) = 5, tan(θ) = 2√6
(a) csc(θ) =
(b) cot(θ) =
(c) cos(90 − θ) =
(d) sin(θ) =

EXAMPLE:
Given sin(θ)=4/5 find the indicated trig. functions.

-Draw a right triangle on paper with the tip on the right and the 90* in the bottom right. Place θ in the bottom left corner. This is the triangle produced in the first quadrant of the circle. Now, we know that sin(θ) = Opp/Hyp. So, we know that the opposite side is equal to 4 and the hypotenuse is equal to 5. Using the Pythagorean Theorem we can find the length of the adjacent side. Now we can find all trig. functions for the triangle.

cos(θ)=3/5 ; tan(θ)=4/3 ; csc(θ)=5/4 ; sec(θ)=5/3 ; cot(θ)=3/4
Note: Answers are not usually this clean. The 3-4-5 right triangle is a special case in which this exists.

Given a calculator you can even solve for θ. If sin(θ)=4/5 then θ=sin^(-1)(4/5) ~= 53 degrees. Note: sin^(-1) is inverse sine.
__________________
Feedback: MCB, SCP, PHOG, PBN, and My eBay account
Siress is offline   Reply With Quote
Old 09-14-2008, 09:34 PM   #15 (permalink)
Bigger Balls
 
Siress's Avatar
 
Join Date: Sep 2006
Location: Atlanta, GA

Find the radian measure of the central angle of a circle of radius r that intercepts an arc of length s.
Radius r Arc Length s Central Angle
83 km 162 km

You should know that for a slice of the circle, like a slice of cake, the radius is the distance from the center to the arc. If you cut your slice with angle θ and have a radius r, the length of the arc between your cuts is equal to θ in radians multiplied by the radius; S = θ*r. If you have your S and r values, then you can solve for θ by dividing both sides of the equation by r. Simplify the fraction if possible.
__________________
Feedback: MCB, SCP, PHOG, PBN, and My eBay account

Last edited by Siress; 09-14-2008 at 09:39 PM.
Siress is offline   Reply With Quote
Old 09-14-2008, 09:42 PM   #16 (permalink)
more gooder
 
dukie's Avatar
 
Join Date: Apr 2008
Location: Kitchener, Ontario

Fan of EMR
CCM Fan
t(angle)=S(arc length)/r ( radius)

t=162/83

t=1.952 radians

180 degrees=Pi radians

1 radian = 180 degrees/pi

1.95 radians = 1.95 * 180 degrees/pi

t=111.78 degrees
__________________
DSGs are in stock
My Feedback
first strike pez dispensers in stock - pm me!
dukie is offline   Reply With Quote
Old 09-14-2008, 09:51 PM   #17 (permalink)
more gooder
 
dukie's Avatar
 
Join Date: Apr 2008
Location: Kitchener, Ontario

Fan of EMR
CCM Fan
That distance is 4042.18 because one is in the norther hemisphere, and one is in the southern. the equator is at 0 degrees. You have to add the angles together, not subtract them. Don't forget to convert the minutes to decimal...
__________________
DSGs are in stock
My Feedback
first strike pez dispensers in stock - pm me!
dukie is offline   Reply With Quote
Old 09-14-2008, 09:55 PM   #18 (permalink)
The Furry Tailed One
 
skiddish9999's Avatar
 
Join Date: Sep 2007
Location: Damn it's hot, Florida

Quote:
Originally Posted by Siress View Post
(I'm procrastinating my homework by doing yours... )

LarPreCalcAGA5 5.2.046.] Use the given function value(s) and trigonometric identities to find the indicated trigonometric functions.
sec(θ) = 5, tan(θ) = 2√6
(a) csc(θ) =
(b) cot(θ) =
(c) cos(90 − θ) =
(d) sin(θ) =

EXAMPLE:
Given sin(θ)=4/5 find the indicated trig. functions.

-Draw a right triangle on paper with the tip on the right and the 90* in the bottom right. Place θ in the bottom left corner. This is the triangle produced in the first quadrant of the circle. Now, we know that sin(θ) = Opp/Hyp. So, we know that the opposite side is equal to 4 and the hypotenuse is equal to 5. Using the Pythagorean Theorem we can find the length of the adjacent side. Now we can find all trig. functions for the triangle.

cos(θ)=3/5 ; tan(θ)=4/3 ; csc(θ)=5/4 ; sec(θ)=5/3 ; cot(θ)=3/4
Note: Answers are not usually this clean. The 3-4-5 right triangle is a special case in which this exists.

Given a calculator you can even solve for θ. If sin(θ)=4/5 then θ=sin^(-1)(4/5) ~= 53 degrees. Note: sin^(-1) is inverse sine.

Yes, I understand that...But, I don't understand how to figure it out with secant and tangent...

And that is funny!

Thank for pointing out one was north one was south...Owell I already submitted the answer.

lets see...wait...secant
hyp/opp

which means the hyp is 5 and opposite side is 1

which means the adjacent side is sqrt (24)

so that would mean all I have to do from there is plug them in?
__________________
MCB FeedBack

Quote:
Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
skiddish9999 is offline   Reply With Quote
Old 09-14-2008, 09:58 PM   #19 (permalink)
Bigger Balls
 
Siress's Avatar
 
Join Date: Sep 2006
Location: Atlanta, GA

It's kind of neat switching between your questions and my own. Any way, last one I think?

Find the distance between the cities. Assume that Earth is a sphere of radius 4000 miles and that the cities are on the same longitude (one city is due north of the other).
City Latitude
Johannesburg, South Africa 26 8' S
Jerusalem, Israel 31 46' N

Ok, this is our slice of pie from the cake. Southern angle of 26 degrees and 8 minutes, northern angle of 31 degrees and 46 minutes. The sum of these is our theta. So, theta is equal to 31 plus 26 degrees and 46 plus 8 minutes. For our formula of S = theta * r, theta must be in radians. You need to convert your minutes to degrees and from degrees to radians. Minutes are in base 60 and degrees are in base 10, so converting is as simple as dividing the amount of minutes by their base (60). Sum up all of your degree values and you have theta in degrees. To convert from degrees to radians, multiple by pi over 180 degrees. The degree units will cancel out and pi will remain; radians being in units of pi. Now you just multiply your theta radians by the radius and you have your distance.
__________________
Feedback: MCB, SCP, PHOG, PBN, and My eBay account
Siress is offline   Reply With Quote
Old 09-14-2008, 10:00 PM   #20 (permalink)
Bigger Balls
 
Siress's Avatar
 
Join Date: Sep 2006
Location: Atlanta, GA

Quote:
so that would mean all I have to do from there is plug them in?
__________________
Feedback: MCB, SCP, PHOG, PBN, and My eBay account
Siress is offline   Reply With Quote
Reply

  mcarterbrown.com » General » General Chat

Thread Tools

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On

Forum Jump


All times are GMT -4. The time now is 11:03 PM.


Powered by vBulletin® Version 3.8.6
Copyright ©2000 - 2015, Jelsoft Enterprises Ltd.
Search Engine Optimization by vBSEO
© MCB Network LLC