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Old 09-14-2008, 11:00 PM   #21 (permalink)
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Quote:
Originally Posted by Siress View Post
Mr. Burns voice...Excellent
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Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
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Old 09-14-2008, 11:05 PM   #22 (permalink)
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By the way, my rate is $20 per degree. It only took me about 10 minutes to answer these so you do the math.

I actually do get paid for this stuff. I'm a college student and tutor others in the Math Lab on campus or One-on-One (at $20 per hour). Trig. is definitely one of the most difficult subjects for students because it gets so involved. Even calculus 3 students have trouble with it on occasion, usually just mixing things up.
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Last edited by Siress; 09-14-2008 at 11:11 PM.
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Old 09-14-2008, 11:13 PM   #23 (permalink)
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Originally Posted by Siress View Post
(I'm procrastinating my homework by doing yours... )

LarPreCalcAGA5 5.2.046.] Use the given function value(s) and trigonometric identities to find the indicated trigonometric functions.
sec(θ) = 5, tan(θ) = 2√6
(a) csc(θ) = 5/sqrt(24)
(b) cot(θ) =1/sqrt(24)
(c) cos(90 − θ) = 1/5
(d) sin(θ) = sqrt(24)/5


correct?

a-1
h-5
o-sqrt(24)

EXAMPLE:
Given sin(θ)=4/5 find the indicated trig. functions.

-Draw a right triangle on paper with the tip on the right and the 90* in the bottom right. Place θ in the bottom left corner. This is the triangle produced in the first quadrant of the circle. Now, we know that sin(θ) = Opp/Hyp. So, we know that the opposite side is equal to 4 and the hypotenuse is equal to 5. Using the Pythagorean Theorem we can find the length of the adjacent side. Now we can find all trig. functions for the triangle.

cos(θ)=3/5 ; tan(θ)=4/3 ; csc(θ)=5/4 ; sec(θ)=5/3 ; cot(θ)=3/4
Note: Answers are not usually this clean. The 3-4-5 right triangle is a special case in which this exists.

Given a calculator you can even solve for θ. If sin(θ)=4/5 then θ=sin^(-1)(4/5) ~= 53 degrees. Note: sin^(-1) is inverse sine.
Hmm...I see...By my calculations...

If you charge 20 for each degree and you only did 10 minutes of work...therefore it's 1/6 of 20 dollars.

$3.33?

Ok, I'll just seal it into a nice lexan block and send it to you...Or would you prefer it in vietnamese dongs? Oh, how about in a post dated check for 2150? Or better yet I could just charge it onto my nigerian bank card...All I need is your social security number...Bank transfer number...
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Quote:
Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
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Old 09-14-2008, 11:17 PM   #24 (permalink)
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I'll have my Nigerian business man contact your Nigerian businessman.
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Old 09-14-2008, 11:19 PM   #25 (permalink)
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Alright, that works, so those are correct then?
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Quote:
Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
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Old 09-14-2008, 11:26 PM   #26 (permalink)
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All but this one: (c) cos(90 − θ) = 1/5

You have the tools to solve it, though. Solve for θ in your given triangle. Then take 90 degrees and subtract θ. Assume the adjacent or opposite side to be equal to 1 and solve for the other sides.
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Old 09-14-2008, 11:33 PM   #27 (permalink)
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Quote:
Originally Posted by Siress View Post
All but this one: (c) cos(90 − θ) = 1/5

You have the tools to solve it, though. Solve for θ in your given triangle. Then take 90 degrees and subtract θ. Assume the adjacent or opposite side to be equal to 1 and solve for the other sides.
Yes, but how do I get theta or rather the angle degree? Solving for it anyway?
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Quote:
Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
skiddish9999 is offline   Reply With Quote
Old 09-14-2008, 11:35 PM   #28 (permalink)
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sin(th)=x
th = inverse sin(x)
th = inverse cos(y)
th = inverse tan(z)
etc...
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Old 09-15-2008, 12:11 AM   #29 (permalink)
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Originally Posted by Siress View Post
sin(th)=x
th = inverse sin(x)
th = inverse cos(y)
th = inverse tan(z)
etc...
Yes, I follow that but how do I get the angle...I've got 48 minutes...
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Quote:
Originally Posted by pizzaluvr View Post
Skiddish is an Elliot Spitzer, if you will.
Most people don't know that skittish is the proper spelling for "jittery". Don't believe me... Look it up.
skiddish9999 is offline   Reply With Quote
Old 09-15-2008, 12:25 AM   #30 (permalink)
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So what is it about upper-lever math that unless you do it regularly, you forget how to do it almost completely? It's almost as if your brain knows it is useless information and automatically files it under "T". Weird.
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