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Old 09-13-2008, 10:50 PM   #1 (permalink)
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Major Trig help needed!

Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90, 0 ≤ θ ≤ π / 2)
Function θ (deg) θ (rad) Function Value
sin π / 3


Find the radian measure of the central angle of a circle of radius r that intercepts an arc of length s.
Radius r Arc Length s Central Angle
83 km 162 km

Ok...I still don't get this one, please, some one help...

LarPreCalcAGA5 5.2.046.] Use the given function value(s) and trigonometric identities to find the indicated trigonometric functions.
sec(θ) = 5, tan(θ) = 2√6
(a) csc(θ) =
(b) cot(θ) =
(c) cos(90 − θ) =
(d) sin(θ) =

Ok...I still don't get this one please some one help...


Find the distance between the cities. Assume that Earth is a sphere of radius 4000 miles and that the cities are on the same longitude (one city is due north of the other).
City Latitude
Johannesburg, South Africa 26 8' S
Jerusalem, Israel 31 46' N

miles


How the hell is this one 4042.183 and not 393.2576

Evaluate the sine, cosine, and tangent of the angle without using a calculator.
240
sin(θ) =
cos(θ) =
tan(θ) =




The circular blade on a saw has a diameter of 6 inches and rotates at 4900 revolutions per minute.
(a) Find the angular speed of the blade in radians per second.
163.3333 513.127
radians/sec

(b) Find the linear speed of the saw teeth (in feet per second) as they contact the wood being cut.
245 128.282
feet/sec




Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90, 0 ≤ θ ≤ π / 2)
Function θ (deg) θ (rad) Function Value
csc DNE




Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90, 0 ≤ θ ≤ π / 2)
Function θ (deg) θ (rad) Function Value
tan 1



Find the indicated trigonometric value in the specified quadrant. Function Quadrant Trigonometric Value
csc(θ) = 5 III cot(θ)


I have no idea how to solve these and I need help because I have a test coming up...My professor reads directly from the book and doesn't teach a damn thing.

Please, for all those whom know how to do trig and can explain things extremely well please help me with these problems.

Thank you very much in advance!
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Last edited by skiddish9999; 09-14-2008 at 08:53 PM.
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Old 09-13-2008, 11:35 PM   #2 (permalink)
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first question -
10-Minute Trig

second question
Arc Length and Area of a sector - Geometry Calculator
you have s and r, calculate it

third question
10-Minute Trig

forth
not sure if that is looking for arc length or direct length. use page 1 or 3 depening

fifth
10-Minute Trig

2pi=180 degrees so 240 degrees = 240*2*pi/180 use the chart on first link to fill in the answers
sixth
saw blade a)
RPM to Rad/sec

saw blade b)

velocity V=r x w ( where v=feet/sec, r=radius( in feet), w=angular velocity ( in rad/sec) calculate it

7th
no idea what the hell DNE means

8th
see 1

9th
no idea what the III is for


any questions, just ask. most of your answers are on the first link, just fill in the numbers and or substitute other values to reduce things to what you know.
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Old 09-14-2008, 10:08 AM   #3 (permalink)
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Quote:
Originally Posted by dukie View Post
7th
no idea what the hell DNE means
DNE = Does Not Exist

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Old 09-14-2008, 01:29 PM   #4 (permalink)
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I hate. Trig. Just ask frontier bill how much Ive been complaining about it lately. Good luck with that. Id probably mess it up if I tried to help you. Sorry.
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Old 09-14-2008, 01:34 PM   #5 (permalink)
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Trig makes the world go round . In reality it's not so nasty. It's cool in EE because you use trig functions ALL THE TIME when talking about signal waveforms. Great stuff.
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Old 09-14-2008, 01:36 PM   #6 (permalink)
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SOHCAHTOA
Sin equals Opposite over Hypotenuse
Cos Adjacent over Hyp
Tan Opp over Adj

just remember that and you can just draw things out on paper and figure out the angles/distances

the same saying works for inverse trig functions also

Inverse Sin of Theta equals Opposite over Hypotenuse etc..
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Old 09-14-2008, 01:39 PM   #7 (permalink)
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Quote:
Originally Posted by Niterocker View Post
DNE = Does Not Exist

-Keith
(hajkowski@aol.com)
Ahh, that makes sense. I would have just used "-" , as in there ain't none
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Old 09-14-2008, 04:39 PM   #8 (permalink)
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Here's a trick for Trig. Memorize the first quadrant of the unit circle (Sin and Cos for θ= 0, pi/6, pi/4, pi/3 and pi/2) and remember that (x,y) = (cosθ, sinθ). You can use those two chunks of information to relate to the other three quadrants, since you know where x and y are positive and negative.

Inverse and hyperbolic functions are easy too, but I don't think you're there yet. If you think any of this is hard, try understanding trigonometric substitution methods of integration... You really have to have a strong foundation in Trig. to get through Analytic Geometry.

Hope this helped,
Seth
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Old 09-14-2008, 04:42 PM   #9 (permalink)
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Quote:
Originally Posted by souz4402 View Post
SOHCAHTOA
Sin equals Opposite over Hypotenuse
Cos Adjacent over Hyp
Tan Opp over Adj

just remember that and you can just draw things out on paper and figure out the angles/distances

the same saying works for inverse trig functions also

Inverse Sin of Theta equals Opposite over Hypotenuse etc..
Inverse Sin of Opposite over Hypotenuse equals Theta.
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Old 09-14-2008, 04:45 PM   #10 (permalink)
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God, I feel stupid now

Good luck brother
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