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09132008, 10:50 PM  #1 (permalink) 
The Furry Tailed One Join Date: Sep 2007 Location: Damn it's hot, Florida  Major Trig help needed!
Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90°, 0 ≤ θ ≤ π / 2) Function θ (deg) θ (rad) Function Value sin ° π / 3 Find the radian measure of the central angle of a circle of radius r that intercepts an arc of length s. Radius r Arc Length s Central Angle 83 km 162 km Ok...I still don't get this one, please, some one help... LarPreCalcAGA5 5.2.046.] Use the given function value(s) and trigonometric identities to find the indicated trigonometric functions. sec(θ) = 5, tan(θ) = 2√6 (a) csc(θ) = (b) cot(θ) = (c) cos(90° − θ) = (d) sin(θ) = Ok...I still don't get this one please some one help... Find the distance between the cities. Assume that Earth is a sphere of radius 4000 miles and that the cities are on the same longitude (one city is due north of the other). City Latitude Johannesburg, South Africa 26° 8' S Jerusalem, Israel 31° 46' N miles How the hell is this one 4042.183 and not 393.2576 Evaluate the sine, cosine, and tangent of the angle without using a calculator. 240° sin(θ) = cos(θ) = tan(θ) = The circular blade on a saw has a diameter of 6 inches and rotates at 4900 revolutions per minute. (a) Find the angular speed of the blade in radians per second. 163.3333 513.127 radians/sec (b) Find the linear speed of the saw teeth (in feet per second) as they contact the wood being cut. 245 128.282 feet/sec Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90°, 0 ≤ θ ≤ π / 2) Function θ (deg) θ (rad) Function Value csc ° DNE Construct an appropriate triangle to complete the table. (0 ≤ θ ≤ 90°, 0 ≤ θ ≤ π / 2) Function θ (deg) θ (rad) Function Value tan ° 1 Find the indicated trigonometric value in the specified quadrant. Function Quadrant Trigonometric Value csc(θ) = –5 III cot(θ) I have no idea how to solve these and I need help because I have a test coming up...My professor reads directly from the book and doesn't teach a damn thing. Please, for all those whom know how to do trig and can explain things extremely well please help me with these problems. Thank you very much in advance!
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09132008, 11:35 PM  #2 (permalink) 
more gooder 
first question  10Minute Trig second question Arc Length and Area of a sector  Geometry Calculator you have s and r, calculate it third question 10Minute Trig forth not sure if that is looking for arc length or direct length. use page 1 or 3 depening fifth 10Minute Trig 2pi=180 degrees so 240 degrees = 240*2*pi/180 use the chart on first link to fill in the answers sixth saw blade a) RPM to Rad/sec saw blade b) velocity V=r x w ( where v=feet/sec, r=radius( in feet), w=angular velocity ( in rad/sec) calculate it 7th no idea what the hell DNE means 8th see 1 9th no idea what the III is for any questions, just ask. most of your answers are on the first link, just fill in the numbers and or substitute other values to reduce things to what you know. 
09142008, 10:08 AM  #3 (permalink) 
Lazy Longballer  DNE = Does Not Exist Keith (hajkowski@aol.com)
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09142008, 01:29 PM  #4 (permalink)  
Brass Monkey Customs 
I hate. Trig. Just ask frontier bill how much Ive been complaining about it lately. Good luck with that. Id probably mess it up if I tried to help you. Sorry.
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09142008, 01:34 PM  #5 (permalink)  
Post Whore 
Trig makes the world go round . In reality it's not so nasty. It's cool in EE because you use trig functions ALL THE TIME when talking about signal waveforms. Great stuff.
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09142008, 01:36 PM  #6 (permalink) 
Corp Por, Kal Vas Flam Join Date: Jul 2008 Location: Spokane, WA 
SOHCAHTOA Sin equals Opposite over Hypotenuse Cos Adjacent over Hyp Tan Opp over Adj just remember that and you can just draw things out on paper and figure out the angles/distances the same saying works for inverse trig functions also Inverse Sin of Theta equals Opposite over Hypotenuse etc.. 
09142008, 04:39 PM  #8 (permalink) 
Bigger Balls Join Date: Sep 2006 Location: Atlanta, GA 
Here's a trick for Trig. Memorize the first quadrant of the unit circle (Sin and Cos for θ= 0, pi/6, pi/4, pi/3 and pi/2) and remember that (x,y) = (cosθ, sinθ). You can use those two chunks of information to relate to the other three quadrants, since you know where x and y are positive and negative. Inverse and hyperbolic functions are easy too, but I don't think you're there yet. If you think any of this is hard, try understanding trigonometric substitution methods of integration... You really have to have a strong foundation in Trig. to get through Analytic Geometry. Hope this helped, Seth
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09142008, 04:42 PM  #9 (permalink)  
Bigger Balls Join Date: Sep 2006 Location: Atlanta, GA  Quote:
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