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Old 10-04-2017, 06:10 PM   #31 (permalink)
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SMA is also high current as well. Wait you already said that haha. I loved my welding class. I miss it

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Seriously.. look up Carbon Arc. We were running in the 400A range to start..
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Old 10-04-2017, 08:49 PM   #32 (permalink)
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Dang. Thats high. I need to look up this welding type. Never heard of it. Thanks for the info

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Old 10-05-2017, 01:03 AM   #33 (permalink)
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Time for a new question. Ok bare with me on this one. I am on my phone and can not draw the simple series network, but i can explain it.

Ok we have E(volt source) 6v>Rs of 2 ohms>RL of 4 ohms>back to 6v source.

Here is the question. It says find the curent IL. Ok no problem its I=V/Rtotal. So its 1 amp.

Ok next part of example it pulls this weird ohms law partial equation. I=V/Rs.... they only divide by ONE of the resisters. I thought the whole point of a series circuit was the same current all through out. Before they get that total current is 1 amp but now we have this
I=V/Rs which is 3 amps.

Ok so by me not knowing exactly what is going on, i decided to try I=V/RL and i get
I=6/4 which is about 1.5 amps but that 1.5 means nothing as well to me. No combination of 1.5 and 3 gets me to 1 amp. So here is my question

WHAT THE HELL IS GOING ON??? haha what is this dividing by a partial resistance and not total to get current? Did i just break ohms law??

Thanks

EDIT
The Rs reaitor is conected to the volt source in series, and RL is conectes to Rs and volt source in series like so

Vs>Rs>RL>back to Vs

So the 3 amps came from dividing the 6v by Rs. What does this 3 amps mean? Thanks

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Last edited by LT72884; 10-05-2017 at 01:08 AM.
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Old 10-05-2017, 07:54 AM   #34 (permalink)
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Kirchhoff's Circuit Laws

Combine what you are learning/have learned of Ohm's Law and combine it with a thorough understanding of what Kirchhoff is saying in his circuit laws. Learn to understand the theory/theories and all of the questions and sub-questions will make a lot more sense.

FYI if no one has told you about it, find your self copies of the Ugly's Manuals. This is the first thing I do with new technicians I hire is make sure they have a set at their bench. Great references in a small concise package.

Side Note - if you think carbon arc welding is high current take a look at Arch Furnaces and some of the larger Inductive Melting Furnaces in the foundry industries. I used to work for Inductortherm Corporation as a Field Engineer helping customers work through problems with their furnaces. Typical Arch Furnaces have 50,000,000 -70,000,000 VA [50 MVA - 70 MVA] rated xfmrs with secondary currents around 55,000amps at 500-1000volts. I used to get crap from utility workers for working with "low voltage" [500-1000 volts] until I showed them how many amps I was working with while troubleshooting problems. Needless to say you take your time and triple check you diagnostic setup before you even think about resetting breakers
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Old 10-05-2017, 09:40 AM   #35 (permalink)
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That really sounds like the question is regarding a parallel circuit.
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Old 10-05-2017, 11:22 AM   #36 (permalink)
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Its definetly series. Its an example in the book. Its something to do with source conversion.

Wow, 50,000 amps. I would not like to be around that. I did not know that there were places that used such high amps to melt metal.

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Old 10-06-2017, 02:28 AM   #37 (permalink)
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3 amps at resiztor RL...After it goes through RL its a Rt and 1 amp....
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Old 10-06-2017, 08:51 AM   #38 (permalink)
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3 amps at resiztor RL...After it goes through RL its a Rt and 1 amp....
Current in series is constant throughout the loop...
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Old 10-06-2017, 08:56 AM   #39 (permalink)
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Take a picture of the problem and post it. Your explanation of it is a bit confusing.
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Old 10-06-2017, 10:36 AM   #40 (permalink)
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Current in series is constant throughout the loop...


While.i understand this, and the whole circuit would be Rt, just trying to figure out what his book question was asking. It does seem like its asking for a parralel wirh series rules.
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